解下列方程组（1）{x+y-z=-3,2x+y-3z=-2,3x-y+2z=-11（2）{5x-4y=0,3y-5z=0,2x-y+z=6

{x-2z=1,4x+z=-14
9x=-27
x=-3
z=-2
y=-2

{x=4y/5,z=3y/5,2x-y+z=6
2*4y/5-y+3y/5=6
8y-5y+3y=30
y=5
x=4
z=3

1）x+y-z=-3 ①2x+y-3z=-2 ②3x-y+2z=-11 ③②+③得：5x-z=-13z=5x+13 ④②-①得：x-2z=1 ⑤④代入⑤得：x-10x-26=1x=-3z=5x+13=-2将x=-3,z=-2代入①得：-3+y+2=-3y=-2所以,原方程组的解为：x=-3,y=-2,z=-22）5x-4y=...