Suppose the fench at left field is 5 feet high and 230 feet from home plate.Determine a new slopevelocity is 120 feet per second,so that the softball will clear the fench by just three foot.formula= y= - 16(1+s^2 )*(x/v)^2+sx+4s=slopev=feet per secondy= height above the ground in feetx= distance on the ground from home plate in feetslope是多少y=-16 (1+s^2)*(233/120)^2 + 233s +4 把230换成233 然后y=0 那么slope的两个直是多少。

问题描述:

Suppose the fench at left field is 5 feet high and 230 feet from home plate.Determine a new slope
velocity is 120 feet per second,so that the softball will clear the fench by just three foot.
formula= y= - 16(1+s^2 )*(x/v)^2+sx+4
s=slope
v=feet per second
y= height above the ground in feet
x= distance on the ground from home plate in feet
slope是多少
y=-16 (1+s^2)*(233/120)^2 + 233s +4 把230换成233 然后y=0 那么slope的两个直是多少。

公式不是直接给出来了么?把各项的值代进去就行了啊.v = 120 feet per secondy = 5 feet highx = 230 feet from home plate代进公式就是5 = -16 (1+s^2)*(230/120)^2 + 230s +4整理一下就是529s^2 - 2070s +538 =0一...