1.(a^2b-ab)-(ab^2+ab)+2(ab^2+ba)2.2(a^2-2ab)-3(-2/3a^2-ab)
问题描述：
1.(a^2b-ab)-(ab^2+ab)+2(ab^2+ba)
2.2(a^2-2ab)-3(-2/3a^2-ab)
答
1.(a^2b-ab)-(ab^2+ab)+2(ab^2+ba)
=(2ab-ab)-(2ab+ab)+2(2ab+ab)
=ab-3ab+2(3ab)
=-2ab+6ab
=4ab
2.2(a^2-2ab)-3(-2/3a^2-ab)
=4a-4ab-3(-4/3a-ab)
=4a-4ab+4a+3ab
=8a-ab
答
1.(a^2b-ab)-(ab^2+ab)+2(ab^2+ba)
=a^2b-ab-ab^2-ab+2ab^2+2ab
=a^2b+ab^2
2.2(a^2-2ab)-3(-2/3a^2-ab)
=2a^2-4ab+2a^2+3ab
=4a^2+ab