﹙x²—36﹚÷﹙2x+12﹚[约分!]

问题描述:

﹙x²—36﹚÷﹙2x+12﹚[约分!]

x^2-36=(x-6)(x+6)
2x+12=2(x+6)
原式=(x-6)/2

﹙x²—36﹚÷﹙2x+12﹚
=[(X+6)(X-6)]÷[2(X+6)]
=(X-6)÷2

﹙x²—36﹚÷﹙2x+12﹚
=[(x-6)(x+6)]/[2(x+6)]
=(x-6)/2