计算(x²+2xy+y²)(x²-xy+y²)²
问题描述：
计算(x²+2xy+y²)(x²-xy+y²)²
答
1. 原式=5x=5x=-5x²y-25x³y
2. 原式=-16x/3+3y+1
3. 原式=x²-4-2x²+10=-x²+6 当x=1时-x²+6=-1²+6=5
4. 说明:∵BE=FD
∴BE+EF=FD+EF
BF=ED
∵∠B=∠D
AB=CD
∴△ABF≌△CDE(SAS)
∴AF=CE(全等三角形对应边相等)
7月S2
答
(x^2+2xy+y^2)(x^2-xy+y^2)^2
=(x+y)^2*(x^2-xy+y^2)^2
=[(x+y)(x^2-xy+y^2)]^2
=(x^3+y^3)^2
答
=(x＋y)²(x－y)²
=[(x＋y)(x－y)]²
=(x²－y²)²
=x^4－2x²y²＋y^4
答
(x²+2xy+y²)(x²-xy+y²)² 还是 [(x²+2xy+y²)(x²-xy+y²)]² ?