对于有理数a、b,定义a⊙b=3a+2b,则[(x+y)⊙(x-y)]⊙3x化简后得( )A. 0B. 5xC. 21x+3yD. 9x+6y
问题描述:
对于有理数a、b,定义a⊙b=3a+2b,则[(x+y)⊙(x-y)]⊙3x化简后得( )
A. 0
B. 5x
C. 21x+3y
D. 9x+6y
答
∵a⊙b=3a+2b,
∴[(x+y)⊙(x-y)]⊙3x
=[3(x+y)+2(x-y)]⊙3x
=(3x+3y+2x-2y)⊙3x
=(5x+y)⊙3x
=3(5x+y)+2×3x
=15x+3y+6x
=21x+3y.
故选C.
答案解析:根据题中所给出的式子进行解答即可.
考试点:整式的加减.
知识点:本题考查的是整式的加减,熟知整式的加减实质上是合并同类项是解答此题的关键.