解方程.50%x+x=150    x÷10%=3003%x+20=60×5645x-12.6=40%x.

问题描述:

解方程.
50%x+x=150    
x÷10%=300
3%x+20=60×

5
6

4
5
x-12.6=40%x.

(1)50%x+x=150,
           1.5x=150,
      1.5x÷1.5=150÷1.5,
              x=100;
(2)x÷10%=300,
     x÷0.1=300,
x÷0.1×0.1=300×0.1,
          x=30;
(3)3%x+20=60×

5
6

   0.03x+20=50,
0.03x+20-20=50-20,
      0.03x=30,
0.03x÷0.03=30÷0.03,
          x=1000;
(4)
4
5
x-12.6=40%x,
     0.8x-12.6=0.4x,
0.8x-12.6-0.4x=0.4x-0.4x,
     0.4x-12.6=0,
0.4x-12.6+12.6=0+12.6,
          0.4x=12.6,
     0.4x÷0.4=12.6÷0.4,
             x=31.5.
答案解析:(1)原式变为1.5x=150,根据等式的性质,两边同除以1.5即可;
(2)原式变为x÷0.1=300,根据等式的性质,两边同乘0.1即可;
(3)原式变为0.03x+20=50,根据等式的性质,两边同减去20,再同除以0.03即可;
(4)原式变为0.8x-12.6=0.4x,根据等式的性质,两边同减去0.4x,得0.4x-12.6=0,两边同加上12.6,得0.4x=12.6,两边同除以0.4即可.
考试点:方程的解和解方程.
知识点:在解方程时应根据等式的性质,即等式两边同加上、同减去、同乘上或同除以某一个数(0除外),等式的两边仍相等,同时注意“=”上下要对齐.