(x的2次方-4x)的2次方-8(4x-x)的平方+16 因式分解,拜托

问题描述:

(x的2次方-4x)的2次方-8(4x-x)的平方+16 因式分解,拜托

=(x²-4x)²+8(x²-4x)+16
=(x²-4x+4)²
=(x-2)的4次方

=(x²-4x)²+8(x²-4x)+16
=(x²-4x+4)²
=(x-2)^4