因式分解:2a(x+1)的2次方-2ax

问题描述:

因式分解:2a(x+1)的2次方-2ax

2a(x+1)²-2ax
=2a*[(x+1)²-x]
=2a(x²+2x+1-x)
=2a(x²+x+1)

4a(2)x(2)+8a(2)x+4a(2)-2ax
括号里的2表示2次方

2a(x+1)²-2ax
=2a*[(x+1)²-x]
=2a(x²+2x+1-x)
=2a(x²+x+1)
底楼错误,因式分解是把一个多项式转化为几个整式的积,不可能有加减号.

2a(x+1)²-2ax
=2a(x²+2x+1-x)
=2a(x²+x+1)