若x²-2x+√(y-1/2)=-1,则x²+4xy+4y²=?

问题描述:

若x²-2x+√(y-1/2)=-1,则x²+4xy+4y²=?

若x²-2x+√(y-1/2)=-1
x²-2x+1+√(y-1/2)=0
(x-1)²+√(y-1/2)=0
x-1=0 y-1/2=0
x=1y=1/2
,则x²+4xy+4y²
=(x+2y)²
=(1+2*1/2)²
=4