x-3分之1+6+2x分之1-x-x²-9分之6
问题描述：
x-3分之1+6+2x分之1-x-x²-9分之6
(x-3)分之1+(6+2x)分之1-x-(x²-9)分之6
答
(x-3)分之1+(6+2x)分之1-x-(x²-9)分之6=1/(x-3) +(1-x)/2(x+3) - 6/(x+3)(x-3)=[2(x+3)+(1-x)(x-3)-12]/2(x+3)(x-3)=(2x+6-x²+4x-3-12)/2(x+3)(x-3)=(-x²+6x-9)/2(x+3)(x-3)=-(x-3)²/2(x+3)(x-3...