解方程（x²+3x+2)(x²-2x-1)(x²-7x+12)+24=0
问题描述：
解方程（x²+3x+2)(x²-2x-1)(x²-7x+12)+24=0
答
(x+1)(x+2)(x^2-2x-1)(x-3)(x-4)+24=0(x+1)(x-3)(x+2)(x-4)(x^2-2x-1)+24=0(x^2-2x-3)(x^2-2x-8)(x^2-2x-1)+24=0,记x^2-2x=t(t-3)(t-8)(t-1)+24=0t^3-12t^2+35t=0t(t-5)(t-7)=0t=0--> x^2-2x=0--> x=0,2t=5--> x^2-2...