化简1/2a^2-5ac-(3a^2c-a^2b)+(3ac-4a^2c)

问题描述:

化简1/2a^2-5ac-(3a^2c-a^2b)+(3ac-4a^2c)

(1/2)a^2-5ac-(3a^2c-a^2b)+(3ac-4a^2c)
=(1/2)a^2 - 2ac -7a^2c+ a^2b
= a(a/2-2c-7ac+ab)

1/2a^2-5ac-(3a^2c-a^2b)+(3ac-4a^2c)
=1/2a^2-5ac-3a^2c+a^2b+3ac-4a^2c
=1/2a^2-2ac-7a^2c+a^2b