求定积分(上限2,下限1)(1/x+1/x^2)dx
问题描述:
求定积分(上限2,下限1)(1/x+1/x^2)dx
没钱了.不管怎么样都错了
答
(1/x+1/x^2)dx
=(lnX-1/X)(从1到2)
=(ln2-1/2)-(ln1-1/1)
=ln2+1/2