(2x²y-3xy²)-3(x²y-2xy²)+2(x²y-4xy²),其中x=-1,y=2.

问题描述:

(2x²y-3xy²)-3(x²y-2xy²)+2(x²y-4xy²),其中x=-1,y=2.
先化简,后求值,

(2x²y-3xy²)-3(x²y-2xy²)+2(x²y-4xy²)=2x²y-3xy²-3x²y+6xy²+2x²y-8xy²=x²y-5xy²=xy(x-5y)将x=-1,y=2.代入得原式=-2×(-1-10)=22