32^2-x=8^x+1求x的值

问题描述:

32^2-x=8^x+1求x的值

7/8

32^(2-x) = 8^(x+1)
2^[5(2-x)] = 2^[3(x+1)]
5(2-x) = 3(x+1)
10-5x = 3x+3
-5x-3x = 3-10
-8x = -7
x= 7/8