几道数学方程,帮忙解下.

问题描述:

几道数学方程,帮忙解下.
5x-3=-x+3
4y-7=6y-9
5(x-1)=3(x+1)
{(2x-1)/3}-{(3x-4)/4}=1
-3(2x+1)+1=-4(5-3x)
{(5x+4)/6}={(x-3)/4}+1
65/100(x-1)+37/100(x+1)+0.1
-2/5(3y+2)=1/10-3/2(y-1)
{(t-3)/2}+{(6-t)/3}=1+{(1+2t)/4}
(各位学姐学长们,帮忙吧,给个过程,本人在此谢过啦.)
对不起啊....是打错了.....
65/100(x-1)=37/100(x+1)+0.1

5x-3=3-x
5x+x=3+3
6x=6
x=1
4y-7=6y-9
4y-6y=7-9
-2y=-2
y=1
5(x-1)=3(x+1)
5x-5=3x+3
5x-3x=5+3
2x=8
x=4
{(2x-1)/3}-{(3x-4)/4}=1 ,等号两边同乘12
4(2x-1)-3(3x-4)=12
8x-4-9x+12=12
-x=4
x=-4
-3(2x+1)+1=-4(5-3x) ,等号两边同乘负一:
6x+3-1=20-12x
18x=18
x=1
{(5x+4)/6}={(x-3)/4}+1 ,等号两边同乘12:
2(5x+4)=3(x-3)+12
10x+8=3x-9+12
7x=-5
x=-(5/7)
65/100(x-1)+37/100(x+1)=0.1 (这题是不是把符号打错了)
65x-65+37x+37=10
102x=38
x=(19/51)
65/100(x-1)=37/100(x+1)+0.1
65x-65=37x+37+10
28x=112
x=4
-2/5(3y+2)=1/10-3/2(y-1) ,等号两边同乘10:
-4(3y+2)=1-15(y-1)
-12y-8=1-15y+15
3y=24
y=8
{(t-3)/2}+{(6-t)/3}=1+{(1+2t)/4} ,两边乘12:
3(t-3)+2(6-t)=12+3(1+2t)
3t-9+12-2t=123+6t
5t=-120
t=-25
符号看清楚了啊..