若幂函数f(x)=x^(2/3),则不等式f(x)>1的解为( )偶函数f(x)在[0,+无穷)上是增函数,且f(log(1/3)^x

问题描述:

若幂函数f(x)=x^(2/3),则不等式f(x)>1的解为( )
偶函数f(x)在[0,+无穷)上是增函数,且f(log(1/3)^x

1 f(x)=x^(2/3)>1
x>1或x2 x> 1/9