(m-n)(p-q)(p+2q)-(n-m)(p+q)(p+2q)
问题描述：
(m-n)(p-q)(p+2q)-(n-m)(p+q)(p+2q)
答
(m-n)(p-q)(p+2q)-(n-m)(p+q)(p+2q)=(m-n)(p-q)(p+2q)+(m-n)(p+q)(p+2q)=(m-n)[(p-q)(p+2q)+(p+q)(p+2q)]=(m-n)(p+2q)[(p-q)+(p+q)]=(m-n)(p+2q)(2p)(m-n)(p-q)(p+2q)-(n-m)(p+q)(p+2q)=(p+2q)[(m-n)(p-q)-(n-m)(p+q...