求log(5x-1)(7x-2)的定义域【(5x-1)是底数】
问题描述:
求log(5x-1)(7x-2)的定义域【(5x-1)是底数】
答
则有:真数:7x-2>0 底数:5x-1>0 且 5x-1≠1 综上解得:x>1/5且x≠2/5
求log(5x-1)(7x-2)的定义域【(5x-1)是底数】
则有:真数:7x-2>0 底数:5x-1>0 且 5x-1≠1 综上解得:x>1/5且x≠2/5