已知梯形ABCD中.AB||CD.E是BC的中点.直线AE交DC的角延长线于点F.求证:三叫形ABE全等三角形FCED``C`````F```````````````E`````````````````A````````B

问题描述:

已知梯形ABCD中.AB||CD.E是BC的中点.直线AE交DC的角延长线于点F.求证:三叫形ABE全等三角形FCE
D``C`````F
``````````
`````E
````````
`````````
A````````B

已知 CE=BE
另外 角CEF=角BEA
又 由AB//CF可知 角BCF=角ABE
所以 根据角角边定理
三角形ABE全等于三角形FCE