lg5+lg20-lg(10的3次方?
问题描述:
lg5+lg20-lg(10的3次方?
答
F=lg5*20/1000=-lg10=-1
答
lg5+lg20-lg10^3
=lg5+1g20-lg1000
=lg((5*20)/1000)
=lg(1/10)
=-1