4(x-1)^2-25(x+1)^2因式分解
问题描述:
4(x-1)^2-25(x+1)^2因式分解
答
4(x-1)^2-25(x+1)^2
=(2x-2+5x+5)(2x-2-5x-5)
=(7x+3)(-3x-7)
=-(7x+3)(3x+7)
答
=[2(X-1)]^2-[5(X+1)]^2
=[2(X-1)-5(X+1)][2(X-1)+5(X+1)]
=(2X-2-5X-5)(2X-2+5X+5)
=(-3X-7)(7X+3)
答
[2(x-1)]2-[5(x+1)]2=(7x+3)(-3x-7)
答
4(x-1)^2-25(x+1)^2
=(2x-2)^2-(5x+5)^2
=(2x-2+5x+5)(2x-2-5x-5)..........平方差公式
=(7x+3)(-3x-7)
=-(7x+3)(3x+7)
答
=(2x-2+5x+5)(2x-2-5x-5)
=(7x+3)(-3x-7)
=-(7x+3)(3x+7)