(X-1)²+|y+2|=0,求多项式-3X²Y-2XY²+2YX²+3XY²的值
问题描述：
(X-1)²+|y+2|=0,求多项式-3X²Y-2XY²+2YX²+3XY²的值
答
(X-1)²+|y+2|=0,
则X-1=0,X=1
y+2=0,y=-2
那么,
-3X²Y-2XY²+2YX²+3XY²
=-X²Y+XY²
=-1²*(-2)+1*(-2)
=2-2
=0