解不等式（x2-5x-17)/(-x2+2x-2)>1
问题描述：
解不等式（x2-5x-17)/(-x2+2x-2)>1
答
右边有0
则a+b=0或a=0
因为b/a分母不等于0
所以a+b=0
b=-a
b/a=-1
所以{1,0,a}={0,-1,b}
a=-1,b=1
b-a=2
答
(x²-5x-17)/(-x²+2x-2)-1>0
(x²-5x-17+x²-2x+2)/(-x²+2x-2)>0
两边乘-1
(2x²-7x-15)/(x²-2x+2)