把分式0.5x-0.2y/(x/3)+2y系数化为整数
问题描述:
把分式0.5x-0.2y/(x/3)+2y系数化为整数
答
0.5x-0.2y/(x/3)+2y
=30*(0.5x-0.2)/[30*(x/3)+2y]
=(15x-6)/(10x+60y)