已知三角形ABC的周长为9,AC=3,4cos2A-cos2C=3.求AB的值.求...
问题描述:
已知三角形ABC的周长为9,AC=3,4cos2A-cos2C=3.求AB的值.求...
已知三角形ABC的周长为9,AC=3,4cos2A-cos2C=3.求AB的值.求sinA的值.
答
4cos2A-cos2C=4(1-2sinA方)-(1-2sinC方)=3-8sinA方+2sinC方=3
sinC=2sinA;所以c=2a;c+a+b=9,b=3,c=4,a=2;AB=c=4.第二题:sinA已知到三边求角度,写不下,自己会吧