2x^2+4xy+2y^2-8z^2因式分解啊
问题描述:
2x^2+4xy+2y^2-8z^2因式分解啊
答
原式=2(x+y)^2-8z^2=2[(x+y)^2-(2z)^2]=2(x+y+2z)(x+y-2z)
2x^2+4xy+2y^2-8z^2因式分解啊
原式=2(x+y)^2-8z^2=2[(x+y)^2-(2z)^2]=2(x+y+2z)(x+y-2z)