-7t^2+6t+1>0.用穿根法怎么求.快,t的取值范围
问题描述:
-7t^2+6t+1>0.用穿根法怎么求.快,t的取值范围
答
-7t²+6t+1>0
7t²-6t-1(7t+1)(t-1)-1/7