设全集U={1,2,3,4,5,6,7,8,9}若A交集B={3},A交集CuB={1,5,7},CuA交集CuB={9}

问题描述:

设全集U={1,2,3,4,5,6,7,8,9}若A交集B={3},A交集CuB={1,5,7},CuA交集CuB={9}
则A=—B=—

A={1,3,5,7} B={2,3,4,6,8,9}解析:A∩B={3},A∩CuB={1,5,7},可知A∩U={1,3,5,7},因为A是U的子集,所以A={1,3,5,7}又A∩CuB={1,5,7},CuA∩CuB={9},则U ∩CuB={1,5,7,9}因为CuB是U的子集,所以CuB={1,5,7,9},则B={2,3,4...