解方程组2(x+2)−3(y−1)＝13.32(x+2)+3(y−1)＝30.7．
问题描述：
解方程组
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2(x+2)−3(y−1)＝13.3 2(x+2)+3(y−1)＝30.7
答
2(x+2)−3(y−1)＝13.3 ① 2(x+2)+3(y−1)＝30.7②
∵①+②得：4（x+2）=44，解得：x=9，
②-①得：6（y-1）=17.4，解得：y=3.9，
∴原方程组的解是：
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x＝9 y＝3.9