(x-1)^2-4(x+2)^2=0怎么解

问题描述:

(x-1)^2-4(x+2)^2=0怎么解

解析
(x-1)²-4(x+2)²=0
x²-2x+1-4(x²+4x+4)=0
x²-2x+1-4x²-16x-16=0
-3x²-18x-15=0
x²+6x+5=0
(x+1)(x+5)=0
x1=-1
x2=-5