4x^2-102x+478.5=0.x等于多少

问题描述:

4x^2-102x+478.5=0.x等于多少

原方程可写成:X^2-25.5 * X=-119.625
即 X^2-25.5 * X+12.75^2=-119.625+12.75^2
得 ( X-12.75)^2=-119.625+12.75^2=42.9375
那么 X-12.75=± 根号42.9375=±6.55
得 X=12.75+6.55=19.3
或 X=12.75-6.55=6.2