(2÷3+3÷7+5÷21)÷21分之1÷0.28等于多少?

问题描述:

(2÷3+3÷7+5÷21)÷21分之1÷0.28等于多少?

(2÷3+3÷7+5÷21)÷21分之1÷0.28
=(2/3+3/7+5/21)*21/0.28
=(2/3+9/21+5/21)*3/0.04
=(2/3+14/21)*300/4
=(2/3+2/3)*300/4
=(4/3)*300/4
=300/3
=100

(2/3+3/7+5/21)/(1/21)*28/100=(14/21+9/21+5/21)*21*7/25=28/21*21*7/25=196/25=7.84

(2÷3+3÷7+5÷21)÷1/21÷0.28
=(2/3+3/7+5/21)×21×25/7
=(2/3×21+3/7×21+5/21×21)×25/7
=(14+9+5)×25/7
=28×25/7
=4×25
=100


原式=(2/3+3/7+5/21)*21/0.28
=[(2/3)*21+(3/7)*21+(5/21)*21]/0.28
=(14+9+5)/.028
=28/0.28
=100

(2÷3+3÷7+5÷21)÷21分之1÷0.28
=(2÷3+3÷7+5÷21)×21÷0.28
=(2÷3×21+3÷7×21+5÷21×21)÷0.28
=(14+9+5)÷0.28
=28÷0.28
=100