计算:1/√0.25+[1/27^(-1/3)]+(√lg^2 3-lg9+1)-lg(1/3)

问题描述:

计算:1/√0.25+[1/27^(-1/3)]+(√lg^2 3-lg9+1)-lg(1/3)

1/√0.25+[1/27^(-1/3)]+(√lg^2 3-lg9+1)-lg(1/3)
=1/0.5+[27^(1/3)]+[√(lg^2 3-lg3²+1)]-lg3^(-1)
=2+3+[√(lg^2 3-2lg3+1)]+lg3
=5+√(1-lg3)²+lg3
=5+1-lg3+lg3
=6