xxx+xxy-2xy-2xx-3x-3y因式分解得多少
问题描述：
xxx+xxy-2xy-2xx-3x-3y因式分解得多少
答
x³+x²y-2xy-2x²-3x-3y
=(x³+x²y)-(2xy+2x²)-(3x+3y)
=x²(x+y)-2x(x+y)-3(x+y)
=(x+y)(x²-2x-3)
=(x+y)(x+1)(x-3)