设A=(1,1,1; 1,1,-1; 1,-1,1),设B=(1,2,3,; -1,-2,4; 0,5,1;) 求AtB

问题描述:

设A=(1,1,1; 1,1,-1; 1,-1,1),设B=(1,2,3,; -1,-2,4; 0,5,1;) 求AtB

B^T=
1 -1 8
2 3 2
0 4 1
A=
1 1 1
1 1 -1
1 -1 1
所以
B^TA
=
(1-1+8 1-1-8 1+1+8
2+3+2 2+3-2 2-3+2
0+4+1 0+4-1 0-4+1)
=
(8 -8 10
8 3 1
5 3 -3)