求解因式分解题
问题描述：
求解因式分解题
1.已知X^2-3X+1=0,求X^4+X^2+1的值
答
X^2-3X+1=0X-3+1/X=0X+1/X=3(X+1/X)^2=9X^2+1/X^2+2=9X^2+1/X^2=7X^2/(X^4+X^2+1)=1/(X^2+1+1/X^2)=1/(X^2+1/X^2+1)=1/(7+1)=1/8 X^2-3X+1=0X={-3±根号(3^2-4)}/2={-3±根号5}/2X^2= { (-3±根号5)/2}^2=（7±3根号...