先化简,再求值:x/x+2-(x^2+2x+1)/x+2÷x^2-1/x-1,其中x=根号3-2
问题描述：
先化简,再求值:x/x+2-(x^2+2x+1)/x+2÷x^2-1/x-1,其中x=根号3-2
答
:x/x+2-(x^2+2x+1)/x+2÷x^2-1/x-1,其中x=根号3-2=x/(x+2)-(x+1)²/(x+2)×(x-1)/(x+1)(x-1)=x/(x+2)-(x+1)/(x+2)=-1/(x+2)=-1/(√3-2+2)=-√3/3;很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么不明白...