三角函数的化简：根号3乘cos²x加上sinxcosx减去（根号3的一半）拜托写写过程.等@

√3/2*(1+cos2x)+1/2*sin2x-√3/2
=sin2x*1/2+cos2x*√3/2
=sin2xcosπ/3+cos2xsinπ/3
=sin(2x+π/3)

根号3cos^2x + sinxcosx -(根号3)/2
=根号3(cos2x+1)/2+1/2sin2x-(根号3)/2
=根号3/2 cos2x+1/2sin2x+(根号3)/2-(根号3)/2
=cos2xcosπ/6+sin2xsinπ/6+(根号3)/2-(根号3)/2
=cos(2x-π/6）

原式=√3(1+cos2x)/2+1/2*sin2x-√3/2
=sin2x*1/2+cos2x*√3/2
=sin2xcosπ/3+cos2xsinπ/3
=sin(2x+π/3)

√3*cos²x+sinxcosx-√3/2
=√3/2*2cos²x+（1/2）*2sinxcosx-√3/2
=√3/2*(1+cos2x)+(1/2)*sin2x-√3/2
=√3/2cos2x+1/2*sin2x
=cos(2x-π/6)