已知:sin(x+π/6)=1/4,求sin(x+7π/6)+cos^2 (5π/6-x)的值

问题描述:

已知:sin(x+π/6)=1/4,求sin(x+7π/6)+cos^2 (5π/6-x)的值

sin(x+7π/6)=sin(x+π/6+π)=-1/4
sin(5π/6-x)=:sin(x+π/6-π)=-1/4
cos^2 (5π/6-x)=1-1/16=15/16
sin(x+7π/6)+cos^2 (5π/6-x)=11/16