已知数列{an}满足2an+1=an+an+2(n=1,2,3,…),它的前n项和为Sn,且a3=5,S6=36. (1)求an; (2)已知等比数列{bn}满足b1+b2=1+a,b4+b5=a3+a4(a≠-1),设数列{an•bn}的

问题描述:

已知数列{an}满足2an+1=an+an+2(n=1,2,3,…),它的前n项和为Sn,且a3=5,S6=36.
(1)求an
(2)已知等比数列{bn}满足b1+b2=1+a,b4+b5=a3+a4(a≠-1),设数列{an•bn}的前n项和为Tn,求Tn

(1)由2an+1=an+an+2得an+2-an+1=an+1-an,则数列{an}是等差数列.                 …(2分)∴a1+2d=56a1+15d=36.⇒a1=1...