已知cos(11π-3)=p,则tan(-3)=?

问题描述:

已知cos(11π-3)=p,则tan(-3)=?
1.已知cos(11π-3)=p,则tan(-3)=?
2.已知f(α)=[sin(π-α)cos(2π-α)tan(-α+3/2π)]/cos(-π-α)
则f(-31/3π)=?

1.
cos(11π-3)=-cos(-3)=-cos(3)=p
cos(3)=-p
∵ π/2