∫1/(x^2-3x+2)dx
问题描述：
∫1/(x^2-3x+2)dx
答
∫1/(x^2-3x 2)dx ＝∫1/(x－1)(x－2)dx＝∫(x－1)－(x－2)/(x－1)(x－2)dx＝∫1/(x－2)dx－∫1/(x－1)dx＝㏑(x－2)／(x－1)＋C
答
你好：
∫1/(x^2-3x+2)dx
=∫1/(x-1)*（x-2）dx
=∫1/(x-2)dx -∫1/(x-1)dx
=ln|x-2|-ln|x-1|
=ln|(x-2)/(x-1)|+C
谢谢