根号下81*82*83*84+1等于几?
问题描述：
根号下81*82*83*84+1等于几?
答
=根号下81*（81+1）*（81+2）*（81+3）+ 1
=根号下[81*（81+3）][（81+1）*（81+2）]+1
=根号下（81^2+3*81)(81^2+3*81+2)+1
=根号下(81^2+3*81)^2+2*(81^2+3*81)+1
=根号下（81^2+3*81+1)^2
=81^2+3*81+1
=6561+243+1
=6805.
答
m=81*（81+1）*（81+2）*（81+3）+ 1
=[81*（81+3）][（81+1）*（81+2）]+1
=（81^2+3*81)(81^2+3*81+2)+1
=(81^2+3*81)^2+2*(81^2+3*81)+1
=（81^2+3*81+1)^2
原式=81^2+3*81+1
=6561+243+1
=6805
答
原式=根号下81*（81+1）*（81+2）*（81+3）+ 1=根号下[81*（81+3）][（81+1）*（81+2）]+1=根号下（81^2+3*81)(81^2+3*81+2)+1=根号下(81^2+3*81)^2+2*(81^2+3*81)+1=根号下（81^2+3*81+1)^2=81^2+3*81+1=6561+243+1...