9(x+2)(x-2)-(3x-2)2 =多少?
问题描述:
9(x+2)(x-2)-(3x-2)2 =多少?
答
是9(x+2)(x-2)-(3x-2) 吧 原式=9(x-2)﹣(9x-12x+4) =9x-36-9x+12x-4 =12x-40 =4(3x-10)
9(x+2)(x-2)-(3x-2)2 =多少?
是9(x+2)(x-2)-(3x-2) 吧 原式=9(x-2)﹣(9x-12x+4) =9x-36-9x+12x-4 =12x-40 =4(3x-10)