函数f(x)=(x^4-10)/(x^2+3),x∈R最小值
问题描述：
函数f(x)=(x^4-10)/(x^2+3),x∈R最小值
答
f(x)=(x^4-10)/(x^2+3) = { (x^4-9) - 1} /(x^2+3) =x^2-3 -1/(x^2+3) = x^2 -1/(x^2+3) - 3
x∈(-∞,0）时,x^2单调减,-1/(x^2+3)单调减,∴f(x)单调减
x∈(-∞,0）时,x^2单调增,-1/(x^2+3)单调增,∴f(x)单调增
∴x=0时有最小值：f(0)=0-1/3-3=-10/3