因式分解:(x+y-2xy)(x+y-2)+(1-xy)2=_.
问题描述:
因式分解:(x+y-2xy)(x+y-2)+(1-xy)2=______.
答
(x+y-2xy)(x+y-2)+(1-xy)2
=(x+y)2-2(1+xy)(x+y)+4xy+1-2xy+x2y2
=(x+y)2-2(1+xy)(x+y)+(1+xy)2
=(x+y)2-(1+xy)(x+y)-(1+xy)(x+y)+(1+xy)2
=(x+y)(x+y-1-xy)-(1+xy)(x+y-1-xy)
=(x+y-1-xy)(x+y-1-xy)
=(x+y-1-xy)2 .
故答案为:(x+y-1-xy)2 .