tan29°+tan31°+√3tan29°tan31°
问题描述:
tan29°+tan31°+√3tan29°tan31°
答
tan(a+b)=(tana+tanb)/(1-tanatanb)
tana+tanb=(1-tanatanb)tan(a+b)
tan29°+tan31°+√3tan29°tan31°
=(1-tan29°tan31°)*tan(29+31°)+√3tan29°tan31°
=√3