计算:(x-y)∧3 × (y-x)∧2 × (y-x)∧5
问题描述：
计算:(x-y)∧3 × (y-x)∧2 × (y-x)∧5
答
= -(x-y)^10我想要过程(x-y)^3 × (y-x)^2 × (y-x)^5=(x-y)^3 × (-(x-y))^2 × (-(x-y))^5= (x-y)^3 × (-1)^2 × (x-y)^2 × (-1)^5 × (x-y)^5= (-1)^7 × (x-y)^10= -(x-y)^10谢谢你